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角行程气动执行机构选型

 

气动执行机构的选用Selection of pneumatic operation organ

 

 

类型:双作用气动执行器

要考虑安全系数,建议在正常扭矩上增加20% - 30%余量。

例如:这个阀门的扭矩需要l00Nm.则考虑安全系数的扭

矩应该是100 ( 1+30%) =130Nm,假如气源压力=0.5MPa,

根据上面的选型表,可以选择这个最小型号为C110DA。

TypeDouble acting pneumatic actuator

To consider the safety factor,It is recommended torque on

the normal increase of 20% - 30% margin.
For example: This valve torque needs l00Nm. Then consider the safety factor of the torsional
Moment should be 100 (1 +30%) = 130Nm, if the gas supply pressure = 0.5MPa ,
Based on the above selection table, Ican choose the smallest model C110DA

单动作Single action :
输出力矩有两种There are two kinds of output torque ;
第一、压缩空气压缩弹簧后所得。在这种情况下,气源压力推动活塞所产生的力减去弹簧压缩后产生的反作用力,输出力矩则从起点的最大值,逐渐递减直至90°为最小值。
First,it is gained by compressing the spring resulting from compressing air.In such condition ,force created by pressure of air supply forcing pistons subtracts created by compressed spring,and output torque descends gradually from max.of jumping-off till 90°which is minimum.
第二;当失气时弹簧的恢复力所得。在这种情况下,由于弹簧的逐渐伸长,输出力矩从90°时的最大值,,递减到0°时的最小值。
Second,it is gained by resting force of spring when air exhausts.In such condition,because of gradual elongation of spring,output torque descends from max.of 90°to minimum of 0°.
例;阀门力矩=80N.m; 可靠系数; (20%);气源压力=0.4Mpa

执行机构力矩=80×1.2=96N.m
查表,在0.4Mpa压力下,被选用的单作用执行机构是C140SRK7
在气源压力的作用下,最小扭矩135N.m
弹簧复位时,最小扭矩;95.9N.m

 

 

弹簧Spring

气压Air pressure

For example; valve moment =80N.m
Confidence coefficient (20%)
Pressure of air supply =0.4Mpa
Torque of operation organ =80×1.2=96N.m
Refer to list,the selected single action operation organ is C140 SR K7
while under air source pressure,minimum torque is 135N.m
when the spring resets,minimum torque is 95.9N.m

点击次数:  更新时间:2011-10-26  【打印此页】  【关闭
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